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153+60x+8x^2=49
We move all terms to the left:
153+60x+8x^2-(49)=0
We add all the numbers together, and all the variables
8x^2+60x+104=0
a = 8; b = 60; c = +104;
Δ = b2-4ac
Δ = 602-4·8·104
Δ = 272
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{272}=\sqrt{16*17}=\sqrt{16}*\sqrt{17}=4\sqrt{17}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-4\sqrt{17}}{2*8}=\frac{-60-4\sqrt{17}}{16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+4\sqrt{17}}{2*8}=\frac{-60+4\sqrt{17}}{16} $
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